Use a javascript variable in the PHP Code -

i want use value of 'n1' variable in 5 , 6 lines off code. means 'n1' variable javascript variable , want use in following php code lines:

var x=50*math.cos((<?php echo posst($streamval[n1][1]); ?>*math.pi)/50)+100; var y=50*math.sin((<?php echo posst($streamval[n1][1]); ?>*math.pi)/50)+75;  <script> (var n1 = 0; n1 <= 3; n1++) {     ctx.beginpath();     ctx.moveto(100,75);     var x=50*math.cos((<?php echo posst($streamval[n1][1]); ?>*math.pi)/50)+100;     var y=50*math.sin((<?php echo posst($streamval[n1][1]); ?>*math.pi)/50)+75;     ctx.lineto(x,y);     x=quarterx(x,y,<?php echo posst($streamval[0][1]); ?>);     y=quartery(x,y,<?php echo posst($streamval[0][1]); ?>);     ctx.font = "10px arial";     ctx.stroketext('<?php echo posst($streamval[0][0]); ?>',x,y);   } </script> 

how can that? thanks.

you dont use javascript variable in php, can create loop in php

<script> <?php ($n1=0;$n1<=3;$n1++){ ?>    ctx.beginpath();    ctx.moveto(100,75);    var x=50*math.cos((<?php echo posst($streamval[$n1][1]); ?>*math.pi)/50)+100;    var y=50*math.sin((<?php echo posst($streamval[$n1][1]); ?>*math.pi)/50)+75;    ctx.lineto(x,y);    x=quarterx(x,y,<?php echo posst($streamval[0][1]); ?>);    y=quartery(x,y,<?php echo posst($streamval[0][1]); ?>);    ctx.font = "10px arial";    ctx.stroketext('<?php echo posst($streamval[0][0]); ?>',x,y);   <?php } ?> </script>   

it works?