mysql - How to get row position from sql table in Php -

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i need 'position (row)' sql table using php script. tested sql statement , worked fine. output correct.

my sql statement:

set @rownum = 0;  select position, name,cash (select name, cash, @rownum := @rownum + 1 position 'my_db'.'cash' order cash desc ) t name = 'user44';

output:

"position":44,"name":"user44","cash":"5600"

but if put in php:

$query="set @rownum = 0; select position, name,cash (select name, cash, @rownum := @rownum + 1 position 'my_db'.'cash' order cash desc ) t name = 'user44';";

it shows me errant query.

i tried this:

$query="select position, name,cash (select name, cash, @rownum := @rownum + 1 position 'my_db'.'cash' order cash desc ) t name = 'user44';";

output:

"position":null,"name":"user44","cash":"5600"

thanks volkerk, solved problem with:

$query = "set @rownum =0;"; $result = mysql_query($query,$link) or die('errant query: '.$query); $query="select position, name,cash (select name, cash, @rownum := @rownum + 1 position 'my_db'.'hscash' order cash desc ) t name = 'user44'"; $result = mysql_query($query,$link) or die('errant query: '.$query);

i understand better now.

the trick not position, it's number of people have better score user.

sql:

// how cash user make select cash mydb.cash name = :name;  // how many people did better + 1 select count(*)+1 mydb.cash cash > :cash

the contatenated query more complicated, didn't need order whole table, , looks like

select position, name, cash mydb.cash join (     select count(*)+1 position     mydb.cash     cash > (         select cash         mydb.cash         name = :name     ) ) name = :name

or, limit join filtering before joining, :

select position, name, cash (     select name, cash     mydb.cash     name = :name ) join (     select count(*)+1 position     mydb.cash     cash > (         select cash         mydb.cash         name = :name     ) )

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