java - Concatenate bytes to get char -

how 1 concatenate 2 byte primitives 1 char in java? i'm trying this:

byte = 0x01; byte b = 0x02; char c = (char) (a + b);

which gives 0x03. answer want 0x0102.

is there no simple way concatenate primitives? i'm surprised there isn't obvious solution, since seems should easy. maybe there , don't see it. :p

any appreciated. thanks!

by shifting left 8 bits , adding. like,

byte = 0x01; byte b = 0x02; char c = (char) ((a << 8) + b); system.out.println(integer.tohexstring(c));

output is

as pointed out in comments (by @chrismartin) bitwise-or (and i'll add might xor) like

char c = (char) ((a << 8) | b);

and

char c = (char) ((a << 8) ^ b);

to achieve same result. since should write dumb code suggest use whichever find easiest understand.

WINAPI